SOLUTION: Two sides of a right triangle are 5 and 10 inches more than the first side. Using the Pythagorean rule, (a^2 + b^2 = c^2), where "c" is the longest side find all three lengths

Question 956142: Two sides of a right triangle are 5 and 10 inches more than the first side. Using the Pythagorean rule, (a^2 + b^2 = c^2), where "c" is the longest side find all three lengths
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
a=short side; b=middle side=a+5in; c=long side=hypotenuse=a+10in

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=400 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 15, -5. Here's your graph:

a=15 ANSWER 1: The shortest side is 15 inches.
b=a+5in=15in+5in=20in ANSWER 2: The middle side is 20 inches long.
c=a+10in=15in+10in=25in ANSWER 3: The hypotenuse is 25 inches.
CHECK:

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