SOLUTION: leg A 15
Leg B x
Hypotenuse 4x
Algebra.Com
Question 916715: leg A 15
Leg B x
Hypotenuse 4x
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
a^2 + b^2 = c^2
15^2 + x^2 = (4x)^2
225 + x^2 = 16x^2
225 = 16x^2 - x^2
225 = 15x^2
15x^2 = 225
x^2 = 225/15
x^2 = 15
x = sqrt(15)
Leg A: 15
Leg B: sqrt(15)
Hypotenuse: 4*sqrt(15)
Let me know if you need more help or if you need me to explain a step in more detail.
Feel free to email me at jim_thompson5910@hotmail.com
or you can visit my website here: http://www.freewebs.com/jimthompson5910/home.html
Thanks,
Jim
RELATED QUESTIONS
leg a: 10cm
hypotenuse: 8cm
leg b: ? (answered by Alan3354)
what is leg A if 15 is the hypotenuse and leg B is 6
(answered by Alan3354)
Leg A= x^2
Leg B= x^2
Hypotenuse= 8.5 in
What is... (answered by ikleyn)
hypotenuse c =17, leg a= 8 what is leg... (answered by algebrahouse.com)
If …
Leg a= x ft
Leg b= 30 ft
Leg c= (x + 10) ft
What is the hypotenuse (Leg c)?... (answered by macston)
leg = 6,hypotenuse = 10
leg = 30,leg =... (answered by arallie)
FIND THE MISSING LENGTH.
LEG A: X
LEG B: X
HYPOTENUSE: 6 times the square root of... (answered by checkley77)
the hypotenuse is 138.56, and leg B is 120 what is leg... (answered by Alan3354)
Hello what is the hypotenuse of :
Leg a : 18cm
Leg b :... (answered by sheldonbbtrocks)