SOLUTION: You are to run a conduit diagonally across a parking lot that is 200 ft long and 60 ft wide. How much conduit will you need to complete this run? Round your answer to tenths. My

Question 868415: You are to run a conduit diagonally across a parking lot that is 200 ft long and 60 ft wide. How much conduit will you need to complete this run? Round your answer to tenths.
My answer: I used Pythagorean theorem a^2+b^2=c^2
So in this case hypotenuse is the 200 ft and 60 ft wide is one of the legs
So you end up with a^2 or b^2 so I had to pick a side. I chose b.
So you rewrite the formula: b^2-C^2=a^2
so you have 60^2-200^2= a^2
once you figured out a^2, you take the square root of that number and plug it back in to the original Pythagorean Theorem.

Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
You misidentified the segments.

200 feet is one dimension's size of the parking lot; and 60 feet is the other dimension of the parking lot at a right angle to the 200 foot one. The diagonal is the hypotenuse of the right triangle formed. The hypotenuse is the length of the conduit to lay along the diagonal.

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