SOLUTION: find x when the long leg is 4(x+2), the short leg is (x+3) and the hypotenuse is 25

SOLUTION: find x when the long leg is 4(x+2), the short leg is (x+3) and the hypotenuse is 25

Algebra.Com

Question 785658: find x
when the long leg is 4(x+2), the short leg is (x+3) and the hypotenuse is 25
Answer by xinxin(76) (Show Source): You can put this solution on YOUR website!
(4*(x+2))^2 + (x+3)^2 = 25^2
x = 4 or -8.12
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