SOLUTION: The hypotenuse of right triangle is twice as long as one of the legs and eight inches longer than the other What are the lengths of the sides of the triangle?

Question 636954: The hypotenuse of right triangle is twice as long as one of the legs and eight inches longer than the other What are the lengths of the sides of the triangle?
Found 2 solutions by reviewermath, graphmatics:
Answer by reviewermath(1029) (Show Source): You can put this solution on YOUR website!

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=768 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 29.856406460551, 2.14359353944898. Here's your graph:

Therefore x = 29.856406460551, disregard the other root because length cannot be negative.
2x = 59.712812921102
2x - 8 = 51.712812921102
The sides of the triangle to 4 decimal places are
29.8564, 51.7128, and 59.7128.
Answer by graphmatics(170) (Show Source): You can put this solution on YOUR website!
Let a and b be the sides of the right triangle and c be the hypotenuse. We are given that:
c=2*a
c=b+8
Being a right triangle
,putting each of the expressions for c into this equation we get:

From equation one we get that
Put this into equation two:

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=3072 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 51.712812921102, -3.71281292110204. Here's your graph:

b=51.71 So c=59.71 a=59,71/2=29.85
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