Hi,

Right Triangle with Sides x, (x+1) and (x+2)...

Applying the Pythagorean Theorem

 x^2 + (x+1)^2 = (x+2)^2

 x^2 + x^2 + 2x + 1 = x^2 + 4x + 4

     x^2 -2x - 3 = 0

 factoring

   (x-3)(x+1) = 0

     x = 3   (throwing out negative solution -1 for length)

 Sides are 3, 4, 5 

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