SOLUTION: It is my 2nd day in my geometry class, I have switched from an online school & I have an upcoming test on slope/midpoint/distance. Im stuck on a question from the study guide becau

Question 568107: It is my 2nd day in my geometry class, I have switched from an online school & I have an upcoming test on slope/midpoint/distance. Im stuck on a question from the study guide because I was not there for the lessons. I need help ASAP!
The question is:
The length of a rectangle is three times as long as it is wide. If the length of the diagonal is 10sqrt6 feet, find the area of the rectangle.
I cannot solve for this question no matter what I try!
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
if x is the width, then 3x is the length

by Pythagoras ___ x^2 + (3x)^2 = [10sqrt(6)]^2 ___ x^2 + 9x^2 = 10^2 * [sqrt(6)]^2

10x^2 = 600 ___ x^2 = 60

the area is ___ x * 3x ___ or 3x^2

3(60) = 180
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