SOLUTION: This is correct: c^2=a^2+b^2 c^2=1^2+1^2 c^2=1+1 c^2=2 c=squrt2 c=1.414

Algebra.Com
Question 548430: This is correct:
c^2=a^2+b^2
c^2=1^2+1^2
c^2=1+1
c^2=2
c=squrt2
c=1.414

Why is this wrong?
c^2=a^2+b^2
c^2=1^2+1^2
c^2=2^2 Added similar terms: same base no.1;and exponent no,2.
c^2=squrt 2^2
c=2 which is not 1.414



Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
It's incorrect because in general


So it's best to follow the first set of steps.

RELATED QUESTIONS

1. (a+b)^2-c^2 / (a+b+c) = ..... (answered by robertb)
1.(I.E)>C 2.C>~C / I (answered by jim_thompson5910)
Need help factoring this : c^2-1/c^4-1/c+1/c^2+1 = (answered by greenestamps)
c/3-2=1 (answered by stanbon)
Ab + 2 = c -... (answered by greenestamps,josgarithmetic)
2(1+c)-(2+c)=10 (answered by checkley77)
(c+6)^2-(c-1)^2 (answered by Alan3354)
(c) 25/2 + 1/2 (answered by richwmiller)
tan(270°+arccot1/2) is =? a 1/2, b -1/2, c 2, d -2 (answered by MathLover1)