SOLUTION: pythagoras=25^2
sides= (x+3)
4(x+2)
Algebra.Com
Question 505231: pythagoras=25^2
sides= (x+3)
4(x+2)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
pythagoras=25^2
sides= (x+3)
4(x+2)
---------------------
(x+3)^2 + (4(x+2))^2 = 25^2
----
x^2 + 6x + 9 + 16(x^2+4x+4) = 625
---
17x^2 + 70x +73 = 625
----
17x^2 + 70x - 552 = 0
---
x = 4
==========
side: x+3 = 7
side: 4(x+2) = 24
========================
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