SOLUTION: 10^2 + The height of a wall is 10 ft, and a pole leans against it so that the pole reaches the top of the wall. If the bottom of the pole is moved 1 foot farther from the base of

Question 495874: 10^2 + The height of a wall is 10 ft, and a pole leans against it so that the pole reaches the top of the wall. If the bottom of the pole is moved 1 foot farther from the base of the wall, the pole will fall. What is the height of the pole?
I wasnt sure if this was as simple as:
10^2 +1^2= height of the pole^2 So that'd be sqrt(101) = height of the pole?
I suppose I'm caught on not being given whether the pole begins completely parallel to the wall, or whether the pole begins, say 5 feet from the wall but 6 feet would make it fall.

Thanks so much for your help!
Answer by cleomenius(959) (Show Source): You can put this solution on YOUR website!
I agree, the question is poorly stated.
I assume you mean the length of the pole
10^2 + x^2 = pole^2.
My answer would be the square root of 100 + (x+1)

This would be the length of the pole that would cause it to fall.
Anything less it should not fall.
cleomenius.

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