SOLUTION: ABC is an right angled triangle,right angled at B.Internal bisector of angle B meet AC at D.AB=3cm,BC=4 cm, find AD.

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Question 468892: ABC is an right angled triangle,right angled at B.Internal bisector of angle B meet AC at D.AB=3cm,BC=4 cm, find AD.
Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
ABC is an right angled triangle,right angled at B.Internal bisector of angle B meet AC at D.AB=3cm,BC=4 cm, find AD.
 

Looking at the big right triangle ABC, and the
fact that the tangent is 



Use the inverse tangent on a calculator to find ∠A:

∠A = 53.13010235°

We know that ∠ABD is 45° because BD bisects the right angle at B

We find ∠ADB by using the fact that
the sum of the interior angles of ᅀABD is 180°

∠A + ∠ABD + ∠ADB = 180° 

∠ADB = 180° - ∠A - ∠ABD

∠ADB = 180° - 53.13010235° - 45° = 81.86989765°

So we use the law of sines:



Cross-multiplying:



Divide both sides by :
  




Work out the right side with a calculator:

AD = 2.142857143cm

Edwin

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