ABC is an right angled triangle,right angled at B.Internal bisector of angle B meet AC at D.AB=3cm,BC=4 cm, find AD.
Looking at the big right triangle ABC, and the
fact that the tangent is
Use the inverse tangent on a calculator to find ∠A:
∠A = 53.13010235°
We know that ∠ABD is 45° because BD bisects the right angle at B
We find ∠ADB by using the fact that
the sum of the interior angles of ᅀABD is 180°
∠A + ∠ABD + ∠ADB = 180°
∠ADB = 180° - ∠A - ∠ABD
∠ADB = 180° - 53.13010235° - 45° = 81.86989765°
So we use the law of sines:
Cross-multiplying:
Divide both sides by :
Work out the right side with a calculator:
AD = 2.142857143cm
Edwin