SOLUTION: The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm what are the dimensions (length and width) of the rectangle. to start i get

Question 46607: The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm what are the dimensions (length and width) of the rectangle.
to start i get
x^2 + (x+1)^2 = 4^2
x^2 + x^2 + 2x + 1 = 16
2x^2 + 2x - 15 = 0
x^2 + x - 7.5 = 0
This is where I can't go futher and I need to turn it in tonight.
Any help please and thank you.
Answer by adamchapman(301) (Show Source): You can put this solution on YOUR website!
You have got to:
Now use the quadratic solver
where a=1, b=1 and c=-7.5
So:

so the two existing solutions are x=8.394 or x=-0.984 (to 3 decimal places)
I hope this helps,
Adam.
P.S. please check out my website, it may be helpful to you:
http://www.geocities.com/quibowibbler
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