SOLUTION: Find the lengths of the sides of the triangles: sides are x and x+1 and the hypotenuse is x+4. So I end up getting x^2 -6x-15= 0 but I don't know how to factor this. What am I doin

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Question 367266: Find the lengths of the sides of the triangles: sides are x and x+1 and the hypotenuse is x+4. So I end up getting x^2 -6x-15= 0 but I don't know how to factor this. What am I doing wrong?
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Find the lengths of the sides of the triangles: sides are x and x+1 and the hypotenuse is x+4. So I end up getting x^2 -6x-15= 0 but I don't know how to factor this. What am I doing wrong?
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It doesn't factor
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=96 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 7.89897948556636, -1.89897948556636. Here's your graph:

Ignore the negative number
x = 3 + 2sqrt(6)
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