SOLUTION: You are planning to put a new digital flat TV on a wall that is 12 ft long and 9 ft high. The digital TV has a diagonal of 72 inches. The length of the TV is twice the width of t

Algebra ->  Algebra  -> Pythagorean-theorem -> SOLUTION: You are planning to put a new digital flat TV on a wall that is 12 ft long and 9 ft high. The digital TV has a diagonal of 72 inches. The length of the TV is twice the width of t      Log On

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Question 361807: You are planning to put a new digital flat TV on a wall that is 12 ft long and 9 ft
high. The digital TV has a diagonal of 72 inches. The length of the TV is twice
the width of the TV. How much of the wall will still need to be decorated
around the TV?
Answer by mananth(12270) About Me  (Show Source):
You can put this solution on YOUR website!
Area of wall = 9*12 = 108 ft^2
...
width of TV = x
Length = 2x
...
diagonal of TV = 72 "= 6 ft
..
x^2+(2x)^2=6^2
x^2+4x^2=36
5x^2=35
x^2=36/5
x = sqrt(36/5)
width = 2.68 ft.
length = 2.68*2=5.36 ft
Area of TV = 2.68*5.36
=14.36ft^2
..
Area of Wall - Area of TV= 108-14.36 = 93.63 ft^2
m.ananth@hotmail.ca