SOLUTION: Using pythagoran theorem & using sine, here's the problem I'm stuck on.
side a= x, side b= unknown, side c = 3x in a right triangle, how do you find side b?
And then to find
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Question 326101: Using pythagoran theorem & using sine, here's the problem I'm stuck on.
side a= x, side b= unknown, side c = 3x in a right triangle, how do you find side b?
And then to find the sine of A & B of a right triangle. A is opposite side x and adjacent to unknown side. B is opposite unknown side and adjacent to side x. What are the angle measures of angle A and angle B?
Thanks for your help!
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Use Pythagoras. Let 
represent the measure of side b.
^2\ =\ x^2\ +\ b^2)
=====================================================
\ =\ \frac{x}{3x}\ =\ \frac{1}{3})
\ =\ \frac{2x\sqrt{2}}{3x}\ =\ \frac{2\sqrt{2}}{3})
Hence the exact answers are:
)
)
Start punching the calculator if you need numeric approximations.
John
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