# SOLUTION: Two of the sides in this isosceles right triangle measure 18 and 3 . How do I solve this ?

Algebra ->  Algebra  -> Pythagorean-theorem -> SOLUTION: Two of the sides in this isosceles right triangle measure 18 and 3 . How do I solve this ?       Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Geometry: Pythagorean theorem Solvers Lessons Answers archive Quiz In Depth

 Question 262259: Two of the sides in this isosceles right triangle measure 18 and 3 . How do I solve this ? Answer by Theo(3458)   (Show Source): You can put this solution on YOUR website!if it's an isosceles triangle, then 2 of the sides must be equal. if it's a right isosceles triangle, then the other 2 angles must be 45 degrees. if 2 of the sides are 3 then the hypotenuse must equal sqrt(18). 3^2 + 3^2 = sqrt(18)^2 becomes 9 + 9 = 18 which would be correct. this is from the pythagorean theorem which states that a^2 + b^2 = c^2 where c is the hypotenuse. I suspect that each side is 3 and the hypotenuse is sqrt(18). otherwise you have no solution based on the information given.