SOLUTION: Computer screen (laptop) Need to find the length of diagonal Height = 9.5" Length = 14" Width = .5" What is the length of diagonal? When I use a tape measure, it comes to

Question 205025: Computer screen (laptop)
Need to find the length of diagonal
Height = 9.5"
Length = 14"
Width = .5"
What is the length of diagonal?
When I use a tape measure, it comes to 17", but it's not working out in the solution. Why?
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
Your measuring tape is close.
The answer is 16.9
a^2+b^2=c^2
9.5^2+14^2=c^2
90.25+196=286.25
sq rt of 286.25=16.9
----------------------------
the formula for solving for the hypotenuse is the Pythagorean theorem
which is side "a" squared plus side "b" squared equals the hypotenuse squared, which is side "c". So then you need to take the sq root of the hypotenuse squared for the answer.
---------------------------------------
a^2 is the way we write "a" squared on the computer. That is where the 2's came from.
Does that help?
Good luck
Bob
RELATED QUESTIONS
If the height of a computer screen is 11 in. and the width is 14 in., what is the length... (answered by ReadingBoosters)

computer screen is 11 in. and the width is 14 in., what is the length of the diagonal?... (answered by Alan3354)

a rectangle flat-screen computer monitor has a diagonal that measures 20 inches. the... (answered by Alan3354)

The screen size of a t.V is the length of the diagonal across the screen. The height of... (answered by jojo14344)

The screen size of a t.V is the length of the diagonal across the screen. The height of... (answered by actuary)

The perimeter of a television screen is 112 inches. The ratio of the length to the width... (answered by Fombitz)

1. triangle with leg 14 and X and hypotenuse x+2. how do you solve that? (answered by MathLover1)

what is the length of the diagonal on a computer screen that measures 39cm by... (answered by Alan3354)

Computer monitor sizes are based on the length of their diagonal distance across the... (answered by macston)