SOLUTION: Find the value of k so that the distance between (k,5) and (5,9) is 5.
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Question 178213This question is from textbook saxon algebra 2
: Find the value of k so that the distance between (k,5) and (5,9) is 5.
This question is from textbook saxon algebra 2
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the value of k so that the distance between (k,5) and (5,9) is 5.
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distance = sqrt((diff in y)^2 + (diff in x)^2)
5^2 = (5-k)^2 + (9-5)^2
25 = k^2-10k+25 + 16
k^2-10k+16 = 0
(k-8)*(k-2) = 0
k = 8, k = 2
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