SOLUTION: Hey how do you solve it when it's like this Leg A: 2x Leb b: x Hypothenose c: 32 I don't get it and the exponents always throws me off and whenever i check it, it comes out

Question 175315: Hey how do you solve it when it's like this
Leg A: 2x
Leb b: x
Hypothenose c: 32
I don't get it and the exponents always throws me off and whenever i check it, it comes out wrong, so please help me
Found 2 solutions by nerdybill, Mathtut:
Answer by nerdybill(5411) (Show Source):
You can put this solution on YOUR website!
Leg A: 2x
Leg b: x
Hypotenuse c: 32
.
Applying Pythagorean theorem:
(2x)^2 + x^2 = 32^2
4x^2 + x^2 = 32^2
5x^2 = 32^2
x^2 = 32^2/5
x = sqrt(32^2/5)
x = 32sqrt(1/5) (exact solution)
OR, approximately:
x = 14.311

Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website!

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x=appx 14.31

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=20480 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 14.3108350559987, -14.3108350559987. Here's your graph: