SOLUTION: Suppose you know the base of a rectangle has a length of 4 inches and a diagonal has a length of 5 inches. Find the area of the rectangle? I'm clueless on this one. I just

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Question 164371This question is from textbook Heart of Mathmatics
: Suppose you know the base of a rectangle has a length of 4 inches and a diagonal has a length of 5 inches. Find the area of the rectangle?

I'm clueless on this one. I just cant seem to get this. Any help would be greatly appreciated.This question is from textbook Heart of Mathmatics

Answer by nerdybill(5411) (Show Source):
You can put this solution on YOUR website!
Because the "diagonal", "base" and "height" of the rectangle forms a "right triangle" we can apply Pythagorean's theorem.
.
Let h = height
then
h^2 + 4^2 = 5^2
h^2 + 16 = 25
h^2 = 9
h = 3 inches
.
Area is then:
"height" * "base"
= 3 * 4 = 12 square inches