# SOLUTION: a standard baseball diamond is a square 90 ft. on a side. find the distance of a throw made from the catcher approximately 3 ft. behind home plate in an attempt to throw out a runn

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 Click here to see ALL problems on Pythagorean-theorem Question 134916: a standard baseball diamond is a square 90 ft. on a side. find the distance of a throw made from the catcher approximately 3 ft. behind home plate in an attempt to throw out a runner trying to steal second baseAnswer by nycsharkman(136)   (Show Source): You can put this solution on YOUR website!A standard baseball diamond is a square 90 feet on a side. Find the distance of a throw made from the catcher approximately 3 feet behind home plate in an attempt to throw out a runner trying to steal second base. Pythagorean theorem: a^2 + b^2 = c^2 We are looking for c + 3 feet (the distance where the catcher is situated behind home plate). We must first find c. (90)^2 + (90)^2 = c^2 16200 = c^2 Take square root of both sides. 127.2792206 = c We can round 127.2792206 to the nearest ones place. Doing this we get: 127 feet = c However, the catcher is 3 feet BEHIND home plate. We add 3 feet to 127 feet and we get 130 feet. Did you follow?