SOLUTION: Could someone help me please? My problem is {{{A^2 + 16^2=3x^2}}} I got to{{{a^2 + 256 = 3x^2}}} i would appreciate it if you could help me on this.

Algebra ->  Algebra  -> Pythagorean-theorem -> SOLUTION: Could someone help me please? My problem is {{{A^2 + 16^2=3x^2}}} I got to{{{a^2 + 256 = 3x^2}}} i would appreciate it if you could help me on this.      Log On

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Question 133986: Could someone help me please? My problem is A%5E2+%2B+16%5E2=3x%5E2 I got toa%5E2+%2B+256+=+3x%5E2 i would appreciate it if you could help me on this.
Answer by ankor@dixie-net.com(12701) About Me  (Show Source):
You can put this solution on YOUR website!
: Could someone help me please? My problem is A^2 + 16^2=3x^2 I got to a^2 + 256 = 3x^2 i would appreciate it if you could help me on this.
:
If you are solving for A it would be:
:
A^2 + 256 = 3x^2
A^2 = 3x^2 - 256; subtracted 256 from both sides
A = sqrt%283x%5E2+-+256%29; find the square root of both sides
:
If you are solving for x:
3x^2 = A^2 + 256
x^2 = %28%28A%5E2+%2B+256%29%29%2F3; divide both sides by 3
x = sqrt%28%28A%5E2+%2B+256%29%2F3%29