SOLUTION: ∠A is an acute angle in a right triangle. Given that sinA=725, what is the ratio for cosA? Enter your answer in the boxes as a fraction in simplest form
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Question 1192801: ∠A is an acute angle in a right triangle. Given that sinA=725, what is the ratio for cosA? Enter your answer in the boxes as a fraction in simplest form
Found 2 solutions by ikleyn, Alan3354:
Answer by ikleyn(52778) (Show Source): You can put this solution on YOUR website!
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∠A is an acute angle in a right triangle. Given that sinA=725, what is the ratio for cosA?
Enter your answer in the boxes as a fraction in simplest form
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Sin(A) can not be equal to 725.
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Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
∠A is an acute angle in a right triangle. Given that sinA=725, what is the ratio for cosA? Enter your answer in the boxes as a fraction in simplest form
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There is a solution for sin(A) = 725, but it's a complex number.
I doubt that's what you meant to ask.
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I suspect it's sin(A) = 7/25
Then cos(A) = sqrt(1 - sin^2) = sqrt(1 - 49/625) = sqrt(576/625)
cos(A) = 24/25
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