SOLUTION: Find the equation of a circle that circumcribes a quadrilatiral with vertices at (-3,6);(-3,0);(3,0); and (3,6).

Question 1189936: Find the equation of a circle that circumcribes a quadrilatiral with vertices at (-3,6);(-3,0);(3,0); and (3,6).

Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

The form for the equation is

where (h,k) is the center and r is the radius.

The given vertices describe a square with side length 6. The center of the circle is the center of the square.

(1) Draw a sketch using the given vertices
(2) Determine the center (h,k)
(3) The radius r is the distance from the center to any of the vertices -- or, if you prefer, it is half the length of the diagonal of the square

You now have h, k, and r -- write the equation.

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