SOLUTION: How do I find the Velocity of an object after it has fallen 20 feet
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Question 1127208: How do I find the Velocity of an object after it has fallen 20 feet
Found 3 solutions by Boreal, MathLover1, Alan3354:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
V=gt
time to fall a certain distance is s=(1/2)at^2
so 40=at^2
40=9.8 m/sec*t^2; t^2=4.08 sec, t=2.02 sec
Therefore, velocity is 9.8 m/sec^2*2.02 sec or 19.8 m/sec
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
the Velocity of an object after it has fallen feet
The formula for a falling object is:
Consider a body of mass m, acted on by a force F for time t. This produces an acceleration which we will designate with the letter g. The body has an initial velocity u, and after time t, it reaches a velocity v. It also travels a distance s.
where
= initial velocity (= for a falling object)
= acceleration due to gravity, ( for English units, or for SI units)
= time, in
=distance that body travels
Newton's equations of motion allow us to work out any of these parameters once we know three other parameters. So the three formulas are:
In terms of distance fallen,
where = distance fallen, ft.
Because and , therefore
Answer:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Velocity is not the same as speed.
Velocity is a vector, includes speed and direction.
speed is a scalar, just a number.
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