SOLUTION: If the diagonal of a swuare is 42.5cm long, find I) the perimeter II) the area Of the square

Question 1120603: If the diagonal of a swuare is 42.5cm long, find
I) the perimeter
II) the area
Of the square
Found 3 solutions by addingup, ikleyn, MathTherapy:
Answer by addingup(3677)   (Show Source): You can put this solution on YOUR website!
A square divided by a diagonal becomes two 45-45-90 triangles. this is a special type of triangle. in this triangle, the two short sides are
= sqrt(hypotenuse)
= sqrt(42.5) = 6.52
I) The perimeter of the square: 6.52 x 4 = 26.08
II) The area: Side^2 = 6.52 x 6.52 = 42.51
Answer by ikleyn(52792)   (Show Source): You can put this solution on YOUR website!
.

(I) If "a" is the side of the square, then, according to Pythagoras, = , = = = 903.125 =====> a = = 30.05 cm. Then the perimeter of the square is 4a = 4*30.05 cm = 120.2 cm. (II) The area of the square is = = 903.0025 square centimeters.

The solution by the other tutor is absolutely incorrect, and deserves the lowest point.

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
If the diagonal of a swuare is 42.5cm long, find
I) the perimeter
II) the area
Of the square

People like adding up don't have a clue about certain math problems.
In addition, can the areas of 2 triangles that form a square have pretty much the same value as the square's hypotenuse: 42.51 cm² and 42.5 cm?
How can the perimeter of a square be SHORTER than the length of its hypotenuse?
The square does form two 45-45-90 special triangles, but the , with one side of the square being S
We can then say that:
You should now be able to find both the perimeter and area of the square.
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