SOLUTION: Determine the length of an inclined plane whose measure is 10 meters longer than the rise and the run is 8 meters longer than the rise.
So I’m trying to find the hypotenuse.
c2=
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Question 1119154: Determine the length of an inclined plane whose measure is 10 meters longer than the rise and the run is 8 meters longer than the rise.
So I’m trying to find the hypotenuse.
c2= a2+b2
So ‘c’ will be the hypotenuse, ‘a’ and ‘b’ as opposite and adjacent.
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
Let x be the length of the hypotenuse (the length of the inclined plane).
That length is 10 more than the rise, so the length of the rise is x-10.
The run is 8 more than the rise, so the run is (x-10)+8 = x-2.
Then your equation c^2 = a^2+b^2 is
The problem should be easy to solve from there.
The equation is quadratic, so it will have two solutions. One of them yields a negative number for the length of the rise, so it can be ruled out.
Note that the answer is irrational; it is not a "nice" answer.
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