SOLUTION: How much water should be mixed to a 500 mL of 30% solution of alcohol to have a resulting concentration of 20%?
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Question 1062652: How much water should be mixed to a 500 mL of 30% solution of alcohol to have a resulting concentration of 20%?
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
you have 500 milliliters of 30% alcohol solution.
you want to add water to this solution so that it becomes a 20% solution.
the amount of alcohol in the 500 milliliters is .3 * 500 = 150 milliliters.
you want the same amount of alcohol divided by (500 + x) milliliters to be equal to 20%.
your equation would be 150 / (500 + x) = .2
x represents the number of milliliters of water to be added.
multiply both sides of this equation by (500 + x) and divide both sides of this equation by .2 to get:
150 / .2 = 500 + x
simplify to get 750 = 500 + x
solve for x to get x = 250.
you need to add 250 milliliters of water to get a solution that is 20% alcohol.
150 / 500 = .3 = 30%
150 / 750 = .2 = 20%
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