SOLUTION: ABC is a right angled triangle. Right angled at A.P is a length from A perpendicular to BC. Show that:- (a) PA=BC (b) 1/square of small a= 1/square of small b+1/square of c

SOLUTION: ABC is a right angled triangle. Right angled at A.P is a length from A perpendicular to BC. Show that:- (a) PA=BC (b) 1/square of small a= 1/square of small b+1/square of c

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Question 1048385: ABC is a right angled triangle.
Right angled at A.P is a length from A perpendicular to BC.
Show that:-
(a) PA=BC
(b) 1/square of small a= 1/square of small b+1/square of c

Answer by ikleyn(52794) (Show Source): You can put this solution on YOUR website!
.
Doesn't make sense.

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