SOLUTION: You have a right triangle where one leg is 3 more than triple the other leg and the hypotenuse is one unit longer than the longest leg. What are the length of the three sides? solv
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Question 1034791: You have a right triangle where one leg is 3 more than triple the other leg and the hypotenuse is one unit longer than the longest leg. What are the length of the three sides? solve using polynomials
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
You have a right triangle where one leg is 3 more than triple the other leg and the hypotenuse is one unit longer than the longest leg. What are the length of the three sides? solve using polynomials
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leg:: x
other leg:: 3x+3
hypot:: 3x+4
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(3x+4)^2 = x^2 + (3x+3)^2
9x^2 + 24x + 16 = x^2 + 9x^2 + 18x + 9
------
6x = -3
x = -1/2 (that is impossible)
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What happened?
The sum of the leg lengths is x + 3x+3 = 4x+3
And 4x + 3 is greater than the length of the hypotenuse which is 3x+3
----
You cannot have a triangle where the sum of the legs exceeds the
length of the 3rd side.
Cheers,
Stan H.
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