SOLUTION: two legs are x+2
but the hypotenuse is x-2 and x+6
How do you solve this
Algebra.Com
Question 1034049: two legs are x+2
but the hypotenuse is x-2 and x+6
How do you solve this
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
This is not really clear. Do you mean the hypotenuse is (x-2)+(x+6) or (x-2)(x+6)?
If either one, we substitute into
and solve for x...
Please repost...
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