Given: m∠DBA=45°; m∠DEB=45°; Prove: ∠DBC ≅ ∠FEB1. ∠DBA and ∠DBC are supplementary 1. they form a linear pair. 2. m∠DBA + m∠DBC = 180° 2. the measures of supplementary angles total 180° 3. m∠DBA = 45° 3. Given 4. 45° + m∠DBC = 180° 4. Equals may be substituted for equals 5. m∠DBC = 135° 5. Equals 45° may be subtracted from equals 6. ∠DEB and ∠FEB are supplementary 1. they form a linear pair. 2. m∠DEB + m∠FEB = 180° 2. the measures of supplementary angles total 180° 3. m∠DEB = 45° 3. Given 4. 45° + m∠FEB = 180° 4. Equals may be substituted for equals 5. m∠FEB = 135° 5. Equals 45° may be subtracted from equals 6. ∠DBC ≅ ∠FEB 6. Angles with equal measures are congruent. Edwin