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Tutors Answer Your Questions about Proofs (FREE)
Question 145216This question is from textbook
: I need your help here-please
14. (2 pts) How many different ways are there for an admissions officer to select a group of 7 college candidates from a group of 19 applicants for an interview? 19 * 7 at a time = 19*18*17*16*15*14*13
I am not that strong in this field. Can you look over this stuff AND get me the answers when it is done so I know where i may have goofed up?This question is from textbook
Click here to see answer by josmiceli(3013)  |
Question 145605This question is from textbook
: I can't figure this out...could I ask you to help me?? Thank you
13. (4 pts) At an annual flower show, 6 different entries are to be arranged in a row.
a) How many different arrangements of the entries are possible? 6!
b) If the owners of the 1st, 2nd, and 3rd place entries will be awarded prizes of $100, $50, and $25 respectively, how many ways can the prizes be awarded? 6 items taken 3 at a time 6*5*4 = 120 ???
This question is from textbook
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Question 145613: How does this work. Could I please get some help?
2. Select five random numbers between 70 and 100. Calculate the mean, median, mode, and midrange of these numbers. Based on your calculations, which measure of central tendency best represents these numbers?
Click here to see answer by kristina29(1)  |
Question 145891This question is from textbook
: What do you think about this px? Can you help me on this?
2. (5 pts)
Construct a frequency distribution of the ages that 25 randomly selected smokers started smoking:
26 26 25 17 16 16 14 17 21 16
16 18 17 15 15 19 16 17 22 15
19 17 16 27 16
This question is from textbook
Click here to see answer by Edwin McCravy(2922)  |
Question 145886This question is from textbook
: How can I do this. Any suggestions?
Construct a pie chart for the data and analyze the results. Draw a circle. Cut it into four slices with ratio 62, 18, 12, 8 – Results show most women work because they need the income for family of other purposes.This question is from textbook
Click here to see answer by Edwin McCravy(2922)  |
Question 146000This question is from textbook
: could you help me; i am stuck. Please
a) A collection of all the objects to be studied is a sample false (population)
b) A subset or part of the subjects to be studied is a sample true
c) In a frequency distribution the class limits must overlap dont know – would say false
d) Pie charts are best used to plot numbers over a period of time false
e) A frequency distribution should have between 3 and 10 classes dont know -woiuld say true
This question is from textbook
Click here to see answer by stanbon(26297)  |
Question 146008This question is from textbook
: can you show mwe how to do this
7) (8 pts)
Construct a histogram and a frequency polygon for the following frequency distribution
Miles Number of Commuters
Class Frequency
0 - 24 4
25 - 49 10
50 - 74 11
75 - 99 5
100 –124 1
This question is from textbook
Click here to see answer by Edwin McCravy(2922)  |
Question 147503: symbolize the following argument and then use a truth table to determine whether the argument is valid or invalid.
1. Valerie will go out if and only if she does not have homework.
Valerie did not go out
Therefore, Valerie had homework.
p= (for me) Valerie will go out q= She does not have homework.
premise 1 p<--q premise 2 = p^~q conclusion = p <--> ^~q
Is that correct?
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Question 147603: Can someone help me construct this truth table? P->(P ->(Q ^ P)). Now, does this mean that first, you work the Q^P? or do you work the p-> which is inside the ( ) first. Then do you take the result of whichever is used and connect it with p-> which is oustide the ( ). Do that make sense. I'm confused too.
Click here to see answer by Edwin McCravy(2922)  |
Question 156521: Adapted from Algebra and Trigonometry by P. Forester but I have a textbook by Holt
Prove the product of two negatives is a positive
(-x)(-y) = (-1*x)(-1*y) Identity
= (-1)[x*(-1)](y) distributive
= (-1)[-1*x](y)
= [-1*(-1)] xy
= 1*xy
= xy
therefore (-x)(-y) = xy
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Question 159824This question is from textbook
: Could I ask your help?
Lamps which cost $120 wholesale are sold for $192, at a profit of $6 per lamp. How many lamps were in the shipment?
9
10
11
12
13 This question is from textbook
Click here to see answer by vleith(1977)  |
Question 160240: I don't understand the logic proofs
not k
not l then h
j then k
h then j
therefore l
i understand modus tollens, modus ponens, law of sillogysm and law of contrapositives but not how they apply to a proof as long as the above.
i also don't understand how to do the proofs and reasons, the above has 7 of each
Click here to see answer by stanbon(26297)  |
Question 182391: I need help with constructing this proof. Can you help me?
Use the laws of inference to prove that the conclusion is true. Include statements and reasons in your formal proof.
24. Given: c-> b
a v ~b
c
Prove: a
Thank you, sincerely
freakertennis@yahoo.com
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Question 188804: I cannot solve this: I can use: Transportation, Material Implication, Material Equivalence, Exportation, Tautology, Double Negation, Commutation, Association, Distribution, Demorgan's Theorem, Modus Ponems, Modus Tollens, Hypothetical Syllogism, Conjunstion, Simplification, Addition, Constructive Dilemma, Absorption and Disjuntive Syllogism.
1. 1.(T -> S) & (B -> D)
2. ~S v ~D
3. W -> (T & B) Therefore: W -> R
Click here to see answer by jim_thompson5910(13794)  |
Question 188809: I cannot solve this: I can use: Transportation, Material Implication, Material Equivalence, Exportation, Tautology, Double Negation, Commutation, Association, Distribution, Demorgan's Theorem, Modus Ponems, Modus Tollens, Hypothetical Syllogism, Conjunstion, Simplification, Addition, Constructive Dilemma, Absorption and Disjuntive Syllogism.
8. 1. p -> (q -> r)
2. ~ (q & ~r) -> s
3. s -> t
4. t <--> (q & ~s) Therefore: p <--> s
Click here to see answer by jim_thompson5910(13794)  |
Question 188807: I cannot solve this: I can use: Transportation, Material Implication, Material Equivalence, Exportation, Tautology, Double Negation, Commutation, Association, Distribution, Demorgan's Theorem, Modus Ponems, Modus Tollens, Hypothetical Syllogism, Conjunstion, Simplification, Addition, Constructive Dilemma, Absorption and Disjuntive Syllogism.
6. 1. (p v q) -> r
2. r -> (s <--> t)
3. s -> ~t Therefore: ~p v ~t
Click here to see answer by jim_thompson5910(13794)  |
Question 188805: I cannot solve this: I can use: Transportation, Material Implication, Material Equivalence, Exportation, Tautology, Double Negation, Commutation, Association, Distribution, Demorgan's Theorem, Modus Ponems, Modus Tollens, Hypothetical Syllogism, Conjunstion, Simplification, Addition, Constructive Dilemma, Absorption and Disjuntive Syllogism.
4. 1. p <--> q
2. p -> r
3. p -> (r -> s) Therefore: q -> s
Click here to see answer by jim_thompson5910(13794)  |
Question 188825: 1. p <--> q
2. p -> r
3. p -> (r -> s) Therefore q -> s
...so far I've tried this but I got stuck...
4. (p -> q) & (q ->p) 1 equivalence
5. p -> q 4 simplification
6. (q -> p) & (p -> q)4 Commutation
7. q -> p 6 simplification
8. q -> (r ->s) 7, 3 Hypothetical Syllogism
9. (q & r) -> s 8 exportation
10. (r & q) -> s 9 commutation
11. p -> (p & r) 2 Absorption
please help :(
Click here to see answer by jim_thompson5910(13794)  |
Question 188823: I can use: Transportation, Material Implication, Material Equivalence, Exportation, Tautology, Double Negation, Commutation, Association, Distribution, Demorgan's Theorem, Modus Ponems, Modus Tollens, Hypothetical Syllogism, Conjunstion, Simplification, Addition, Constructive Dilemma, Absorption and Disjuntive Syllogism.
10. 1. p -> (q <--> r)
2. ~q -> r
3. ~(q <--> s)
4. p -> s Therefore: ~p
Click here to see answer by jim_thompson5910(13794)  |
Question 188838: I saw that people can solve logic proofs on this site. I've looked everywhere for help. Could I get help with these two?
1. p v (q & r)
2. ~r
3. p -> (s -> ~t) /:. (therefore) ~(s & t)
AND
1. (p <--> q) -> s
2. ~(~r -> t)
3. ~q v ~s /:. (t v p) -> (~t & ~q)
I would write what I have so far but I know that it's really wrong and it just confused me.
Click here to see answer by Edwin McCravy(2922)  |
Question 188933: I cannot solve this: I can use: Transportation, Material Implication, Material Equivalence, Exportation, Tautology, Double Negation, Commutation, Association, Distribution, Demorgan's Theorem, Modus Ponems, Modus Tollens, Hypothetical Syllogism, Conjunstion, Simplification, Addition, Constructive Dilemma, Absorption and Disjuntive Syllogism.
1. p -> (q & r)
2. ~t -> (~r v ~s) Therefore: (p & s) -> t
I know that you must somehow get:
~p
~p v ~s Add
~(p & s) Demorgans
~(p & s) v t Addition
(p & s) -> t Implication OR
~t -> t
t v t Implication
t Tautology
t v ~(p & s) Addition
~(p & s) v t Commutation
(p & s) -> t Implication
But I cannot get the steps before these. Please help!
Click here to see answer by jim_thompson5910(13794)  |
Question 189101: I need to construct a proof using all of the rules: (ex. commutation, association, material implication, exportation, hypothetical syllogism, DeMorgans, Double Negation, Distribution, etc.)
1. (p <--> q) -> s
2. ~(~r -> t)
3. ~q v ~s Therefore: (t v p) -> (~t & ~ q)
Click here to see answer by jim_thompson5910(13794)  |
Question 188928: I cannot solve this: I can use: Transportation, Material Implication, Material Equivalence, Exportation, Tautology, Double Negation, Commutation, Association, Distribution, Demorgan's Theorem, Modus Ponems, Modus Tollens, Hypothetical Syllogism, Conjunstion, Simplification, Addition, Constructive Dilemma, Absorption and Disjuntive Syllogism.
1. ~(p <--> s)
2. (p v q) -> r
3. (t v ~s) -> (~s & ~r) Therefore: ~t & ~p
Click here to see answer by jim_thompson5910(13794)  |
Question 188873: I need to solve using Transportation, Material Implication, Material Equivalence, Exportation, Tautology, Double Negation, Commutation, Association, Distribution, Demorgan's Theorem, Modus Ponems, Modus Tollens, Hypothetical Syllogism, Conjunstion, Simplification, Addition, Constructive Dilemma, Absorption and Disjuntive Syllogism.
1. (p <--> q) -> s
2. ~(~r -> t)
3. ~q v ~s Therefore: (t v p) -> (~t & ~q)
AND this is the other problem
1. p v (q & r)
2. ~r
3. p -> (s -> ~t) Therefore: ~(s & t)
Click here to see answer by jim_thompson5910(13794)  |
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Older solutions: 1..45, 46..90, 91..135, 136..180
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