SOLUTION: not very sure if this is in logic but I need some proof. I need to prove that this sequence {{{1+3+5+7+...}}} ends in {{{n^2+2n-1)}}} any help is very much appreciated than

Question 994880: not very sure if this is in logic but I need some proof.
I need to prove that this sequence ends in
any help is very much appreciated
thanks
Found 2 solutions by Edwin McCravy, ikleyn:
Answer by Edwin McCravy(20054) (Show Source): You can put this solution on YOUR website!

That's false. The sequence ends in Edwin

Answer by ikleyn(52776) (Show Source): You can put this solution on YOUR website!
.
1 + 3 = 4,

1 + 3 + 5 = 9,

1 + 3 + 5 + 7 = 16,

1 + 3 + 5 + 7 + 9 = 25,

and so on. Thus every time you get the sum equal to the square of an integer number.

So yours formula is wrong.

The correct formula is

1 + 3 + 5 + 7 + 9 + . . . + (2n-1) = .

For the proof see the lesson Mathematical induction and arithmetic progressions in this site.

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