SOLUTION: Hey guys, quick question. How do I work to prove this conclusion?
1. (L > I) > (D>A)
2. (L>D) > (D>I)
3. (L>A) > ~(I & A)
4. L>D
Conclusion: ~(I&A)
Any help would be a
Algebra.Com
Question 979816: Hey guys, quick question. How do I work to prove this conclusion?
1. (L > I) > (D>A)
2. (L>D) > (D>I)
3. (L>A) > ~(I & A)
4. L>D
Conclusion: ~(I&A)
Any help would be appreciated!
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Number | Statement | Lines Used | Reason |
---|
1 | (L > I) > (D>A) | | |
2 | (L>D) > (D>I) | | |
3 | (L>A) > ~(I & A) | | |
4 | L>D | | |
:. | ~(I&A) | | |
5 | D > I | 2,4 | Modus Ponens |
6 | L > I | 4,5 | Hypothetical Syllogism |
7 | D > A | 1,6 | Modus Ponens |
8 | L > A | 4,7 | Hypothetical Syllogism |
9 | ~(I&A) | 3,8 | Modus Ponens |
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