I'll try. 1.¬S -> Q 2.(U v P) -> (F v T) 3.(R & S) -> T 4.¬R -> Q 5. Q -> U concl: ¬T -> F 6. ¬T -> ¬(R & S) 3, CP 7. ¬T -> ¬R v ¬S 6, DM 8. ¬R v ¬S -> Q 1,4, disjunctive elimination 9. ¬T -> Q 7,8, HS 10. ¬T -> U 9,5, HS 11. U -> (F v T) 2, simp. 12. ¬T -> (F v T) 10,11 HS 13. (~T -> F) v (¬T -> T) 12, implication is left distributive over disjunction 14. ~T -> F 13, elimination of contradiction (~T -> T) Edwin