I'm going to use & for the "dot" and "->" for "horseshoe"
1. (B & C) -> D
2. B
3. Q -> ~(~C v D)
4. ~Q = T
/ T
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5. B -> (C -> D) 1 Exportation
6. C -> D 5,2 Modus Ponens
7. ~~(C -> D) 6 Double Negation
8. ~Q 3,7 Modus Tollens
9. (~Q -> T) & (T -> ~Q) 4 Material Equivalence
10. ~Q -> T 9 Simplification
11. T 10,8 Modus Ponens
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Let me know if that helps or not. Thanks.
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