SOLUTION: I tried to prove this but I am lost on how to finish or am I done?
Proof:
∀ x, P(x) → R(x) (premise)
¬R(k) (premise) (DeMorgan’s)
∴ ¬P(k) (universal instan
Algebra.Com
Question 903091: I tried to prove this but I am lost on how to finish or am I done?
Proof:
∀ x, P(x) → R(x) (premise)
¬R(k) (premise) (DeMorgan’s)
∴ ¬P(k) (universal instantiation)
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ \right\ R(x))
Premise
)
Premise
Therefore )
Modus Tollens
I have no idea what DeMorgan or Universal Instantiation has to do with anything.
John
My calculator said it, I believe it, that settles it
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