Prove: Q (1) [~(A•C)->Q]•Z : Given (2) [~B v ~(A•C)]•D : Given (3) ~B->Q : Given (4) [~(A•C)->Q] : (1) Conjunction Elimination (5) [~B v ~(A•C)] : (2) Conjunction Elimination (6) Q : (4),(5) Disjunction Elimination Q.E.D.