SOLUTION: Show that for all k and all v>0, ln(v^k) = k(ln v) and log(v^k) = k(log v)
Algebra.Com
Question 443211: Show that for all k and all v>0, ln(v^k) = k(ln v) and log(v^k) = k(log v)
Answer by swincher4391(1107) (Show Source): You can put this solution on YOUR website!
Let
Then
Raise both sides to the n power.
=
ln both sides:
Remember that
Then
Q.E.D. :)
--------------------
Let
Then v =
Raise both sides to the n power
log both sides
Substitute for m back
--------------------
Hope this helped!
RELATED QUESTIONS
Solve for v.... (answered by jim_thompson5910)
1. K > ~K
2. (~S v U)> K
/... (answered by lynnlo,jim_thompson5910)
Q=m-v/k solve for... (answered by Alan3354)
v=(b-u)/k solve for... (answered by Gogonati)
K=1/2mv^2 solve for... (answered by greenestamps)
1. ~(K v F)
2. ~F ⊃ (K v C)
3. (G v C) ⊃ ~H / ~(K v... (answered by Edwin McCravy)
1. ~(K v F)
2. ~F ⊃ (K v C)
3. (G v C) ⊃ ~H /~(K v H)
(answered by CPhill)
suppose that V is finite-dimensional space and T:V->V is a linear operator.
1. prove... (answered by ikleyn)
Solve for L. V = K log base e (1+... (answered by stanbon)