SOLUTION: This one is nuts
A -> (D -> E)
F -> [(A & B) v (A & ~B)]
We have to show (F & D) -> E
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Question 251008: This one is nuts
A -> (D -> E)
F -> [(A & B) v (A & ~B)]
We have to show (F & D) -> E
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Note that [(A & B) v (A & ~B)] is equivalent to A. So
F -> [(A & B) v (A & ~B)] is the same thing as F -> A, hence A -> (D -> E) is the same thing as F -> (D -> E), and (F & D) -> E follows directly.
John
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