SOLUTION: Conditional proof M->(K->L) (L\/N) -> J Therefore, M-> (K->J) That's supposed to be a downward arrow between L and N in the second line

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Question 1177235: Conditional proof
M->(K->L)
(L\/N) -> J
Therefore, M-> (K->J)
That's supposed to be a downward arrow between L and N in the second line

Answer by math_helper(2461)   (Show Source): You can put this solution on YOUR website!

1. M-->(K-->L) Premise
2. (LvN)--> J Premise
// show M-->(K-->J)
3.:: M Conditional Proof (CP) assumption #1
4.:: K-->L 3,1 Modus Ponens (MP)
5.:: K CP assumption #2
6.:: L 5,4 MP
7.:: LvN 6 addition (ADD) [ The free lunch of logic ]
8.:: J 7,2 MP
9.:: K-->J 5-8 CP
10.:: M-->(K-->J) 3-9 CP
11. M-->(K-->J) 3-10 CP
// Notes
Line 3 says assume M is true
Line 4 shows if M is true then it follows K-->L by Premise #1
Line 5 says assume K is true
Line 9 shows the if K is true then J is true (K-->J)
Line 10 just puts together "if M true then it follows K-->J" so M-->(K-->J)
Line 11 discharges CP assumptions and brings the conclusion into the main
argument.

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