SOLUTION: Solve using the methods of Reductio ad Absurdum 1. ~A∙~B ∴ A↔B
Algebra
.Com
Question 1117149
:
Solve using the methods of Reductio ad Absurdum
1. ~A∙~B ∴ A↔B
Answer by
solver91311(24713)
(
Show Source
): You can
put this solution on YOUR website!
Hint: The negation of A <=> B is (A * ~B) V (~A * B)
John
My calculator said it, I believe it, that settles it
RELATED QUESTIONS
Solve use reductio ad absurdum 1. ~P→(R∙S) 2....
(answered by
math_helper
)
How do I solve ~Q → (L → F), Q → ~A, F → B, L, therefore, ~A v B...
(answered by
jim_thompson5910
)
Choose one of the proofs below and use one of the indirect proof techniques (reductio ad...
(answered by
jim_thompson5910
)
I need help constructing an indirect proof using reductio ad absurdum for: ~S → (F...
(answered by
Edwin McCravy
)
Solve the following using rules of replacement: (E → T) ∧ (T → O),...
(answered by
jim_thompson5910
)
∼A∙~B ~D⊃A M⊃[(NvO)⊃P] Q⊃(SvT)...
(answered by
jim_thompson5910
)
1. A→B 2. A→~(C∨B) ∴ ~A 1. (A&~B)&(~C∨D) 2....
(answered by
Edwin McCravy
)
1. (A∨~B)→(F∨(R∙G)) 2. A 3. F→L
(answered by
math_helper
)
8. Write the expression using exponents. Do not solve. b ∙ b ∙ b ∙ b...
(answered by
Edwin McCravy,richard1234
)