SOLUTION: 1. (~F & E) > (G > F)
2. F > ~E
3. E
/~G
Algebra.Com
Question 1061188: 1. (~F & E) > (G > F)
2. F > ~E
3. E
/~G
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Previously answered here
https://www.algebra.com/cgi-bin/jump-to-question.mpl?question=1061177
RELATED QUESTIONS
1. (~F&E) > (G>F)
2. F>~E
3. E
/~G
(answered by jim_thompson5910)
(1). (I&E) > ~ F
(2). F v (G&H)
(3). I = E / (conclusion) I > G (answered by Edwin McCravy)
Two step proof:
1. D > E
2. F > G
3. D v F / E v G
(answered by Edwin McCravy)
3. If f(x)=square root 2x^2-1 and g(x)=x^1/2, find (and simplify)
a) (f+g)(x)
b)... (answered by CPhill)
Given the functions
f(x)=1/x+6 ; g(x)=x/2-x
a.(f ∘ g)(-2)
b.(g ∘ f)(-2)
(answered by stanbon)
1. (I&E) ⊃ ~F 2. F∨(G & H) 3. I≡E/ I⊃G (answered by Edwin McCravy)
1. (E ⊃ A) • (F ⊃ A)
2. E ∨ G
3. F ∨ ∼G / A
(answered by Edwin McCravy)
f(x)=x^2-1 and g(x)=4x+3 evaluate the following.
c. 3f(x)−g(x)=
d. f(g(2)) = ... (answered by Aldorozos)
If f(x)= square root 2x^2-1 and g(x)=x^1/2, find and simplify
a) (f+g)(x)
b) (f-g)(x)
(answered by Alan3354)