SOLUTION: Using an indirect proof to solve this problem:
1. B ⊃ (C ⊃~B)
2. A ⊃ (B ⊃ C) /~A v ~ B
Thank you!
Algebra.Com
Question 1060204: Using an indirect proof to solve this problem:
1. B ⊃ (C ⊃~B)
2. A ⊃ (B ⊃ C) /~A v ~ B
Thank you!
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
The idea is to assume the complete opposite of the conclusion (statement 3).
Then show how that assumption leads to to a contradiction (statement 14).
This contradiction means that the opposite of the assumption must be true. In other words, the original conclusion is true.
Number | Statement | Lines Used | Reason |
---|
1 | | B -> (C -> ~B) | | |
2 | | A -> (B -> C) | | |
:. | | ~A v ~B | | |
| 3 | ~(~A v ~B) | | AIP |
| 4 | ~~A & ~~B | 3 | DM |
| 5 | A & B | 4 | DN |
| 6 | B & A | 5 | Comm |
| 7 | A | 5 | Simp |
| 8 | B | 6 | Simp |
| 9 | C -> ~B | 1,8 | MP |
| 10 | B -> C | 2,7 | MP |
| 11 | B -> ~B | 10,9 | HS |
| 12 | ~B v ~B | 11 | MI |
| 13 | ~B | 12 | Taut |
| 14 | B & ~B | 8,13 | Conj |
15 | | ~A v ~B | 3-14 | IP |
Abbreviations/Acronyms Used
AIP = Assumption for Indirect Proof
Comm = Commutation
Conj = Conjunction
DM = De Morgan's Law
DN = Double Negation
HS = Hypothetical Syllogism
IP = Indirect Proof
MI = Material Implication
MP = Modus Ponens
Simp = Simplification
Taut = Tautology
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