SOLUTION: I need to prove the following:
M->(K->L)
(LvN)->J
/M->(K->J)
Algebra.Com
Question 1005369: I need to prove the following:
M->(K->L)
(LvN)->J
/M->(K->J)
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
| Number | Statement | Lines Used | Reason |
|---|
| 1 | | M -> (K -> L) | | |
| 2 | | (L v N) -> J | | |
| :. | | M -> (K -> J) | | |
| | | 3 | M*K | | ACP |
| | | 4 | (M*K) -> L | 1 | Exp |
| | | 5 | L | 4,3 | MP |
| | | 6 | L v N | 5 | Add |
| | | 7 | J | 2,6 | MP |
| 8 | | (M * K) -> J | 3-7 | CP |
| 9 | | M -> (K -> J) | 8 | Exp |
Abbreviations/Acronyms Used
ACP = Assumption for Conditional Proof
Add = Addition
CP = Conditional Proof
Exp = Exportation
MP = Modus Ponens
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