SOLUTION: Four consecutive even integers have a sum of 508. Find the difference between the largest of the four and 117

Question 999787: Four consecutive even integers have a sum of 508. Find the difference between the largest of the four and 117
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
.
S=smallest integer; X=second integer=S+2
Y=third integer=S+4; L=largest integer=S+6
.
S+X+Y+L=508
S+(S+2)+(S+4)+(S+6)=508
4S+12=508
4S=496
S=124
The smallest integer is 124
L=S+6=124+6=130
The largest integer is 130
.
130-117=13
ANSWER: The difference is 13.

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