SOLUTION: One integer is 6 more than a second integer. Three times the first integer when added to two times the second integer is less than 22. Determine the largest possible values of the
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Question 99967: One integer is 6 more than a second integer. Three times the first integer when added to two times the second integer is less than 22. Determine the largest possible values of the two integers.
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
a=b-6
3a+2b<22
.
replace a with b-6: 3(b-6)+2b<22
3b-18+2b<22
5b-18<22
5b<40
b<8
the largest possible values are: 7 and 1
Ed
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