SOLUTION: Find two consecutive integers such that the sum of the smaller and three times the larger is 39. and Find four consecutive integers whose sum is 72.

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Question 99861: Find two consecutive integers such that the sum of the smaller and three times the larger is 39.
and
Find four consecutive integers whose sum is 72.
Found 2 solutions by checkley71, stanbon:
Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!
X+3(X+1)>39
X+3X+3>39
4X+3>39
4X>36
X>36/4
X>9 ANSWER.
FOR THE PROOF SET X=10
10+3(10+1)>39
10+3*11>39
10+33>39
43>39.
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Find two consecutive integers such that the sum of the smaller and three times the larger is 39.
EQUATION:
x + 3(x+1) = 39
4x+3 = 39
4x=36
x = 9
x+1 = 10
====================

and
Find four consecutive integers whose sum is 72.
EQUATION:
x + (x+1) + (x+2) + (x+3) = 72
4x + 6 = 72
4x = 68
x = 17
x+1 = 18
x+2 = 19
x+3 + 20
=============
Cheers,
Stan H.
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