SOLUTION: Write out the expression: For two consecutive even integers, 5 times the smaller number minus twice the larger is one-fifth of the square of the larger number

Algebra.Com
Question 997807: Write out the expression: For two consecutive even integers, 5 times the smaller number minus twice the larger is one-fifth of the square of the larger number
Answer by CubeyThePenguin(3113)   (Show Source): You can put this solution on YOUR website!
consecutive even integers: x, (x+2)

5x - 2(x+2) = 1/5 * (x+2)^2

RELATED QUESTIONS

given two consecutive positive even integers, it turns out that the square of the larger... (answered by hkwu)
three times the smaller of two consecutive even integers is the same as -146 minus 4... (answered by Maths68)
What are two consecutive even integers such that five times the larger minus four times... (answered by ReadingBoosters)
what are two consecutive even integers. such that five times the smaller minus three... (answered by CubeyThePenguin)
for two consecutive even integers, the sum of the smaller and twice the larger is 58 (answered by ankor@dixie-net.com)
two times the smaller consecutive integer minus the larger is 16. Find the consecutive... (answered by stanbon)
Three times the smaller of two consecutive even integers is the same as -146 minus 4... (answered by algebrahouse.com)
three times the smaller of two consecutive even integers is the same as -146 minus 4... (answered by CubeyThePenguin)
ten times the larger if the two consecutive even integers minus seven times the smaller... (answered by macston)